Start a new Kumite
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Kumite (ko͞omiˌtā) is the practice of taking techniques learned from Kata and applying them through the act of freestyle sparring.

You can create a new kumite by providing some initial code and optionally some test cases. From there other warriors can spar with you, by enhancing, refactoring and translating your code. There is no limit to how many warriors you can spar with.

A great use for kumite is to begin an idea for a kata as one. You can collaborate with other code warriors until you have it right, then you can convert it to a kata.

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Code
Diff
  • -- Code here
    SELECT * FROM customers;
    • -- Code here
    • SELECT * FROM customers;

Closest I can get using the special numbers (pi, e, and golden ratio); about 0.15 off.

Code
Diff
  • import math
    
    def hundred():
        golden = ((1 + 5 ** 0.5)/2)
        return round((math.pi * math.e) ** golden * math.sqrt(math.pi * math.e) + math.pi * golden + golden / math.e + golden / (math.pi ** golden))
    
    • function returnhundred() {
    • return 10 ** 2;
    • }
    • import math
    • def hundred():
    • golden = ((1 + 5 ** 0.5)/2)
    • return round((math.pi * math.e) ** golden * math.sqrt(math.pi * math.e) + math.pi * golden + golden / math.e + golden / (math.pi ** golden))
Code
Diff
  • class Component{
    
      constructor(dom){
        this.dom = dom;
      }
      
      onCreate() {
        return this.dom;
      }
    }
    • function Component(dom) {
    • this.dom = dom;
    • class Component{
    • this.onCreate = function() {
    • constructor(dom){
    • this.dom = dom;
    • }
    • onCreate() {
    • return this.dom;
    • }
    • }
Recursion
Algorithms
Computability Theory
Logic
Theoretical Computer Science

A recursive factorial function.

Factorial = fun (Y, 0) ->  1;
      (Y, N) -> N * Y(Y, N - 1)
  end,

io:format("~p~n", [Factorial(Factorial, 5)]),

init:stop().
Code
Diff
  • def multiply_and_add_one(a, b): 
        return a * b + 1
    • def multiply_and_add_one(a, b):
    • r = a * b
    • return r + 1
    • def multiply_and_add_one(a, b):
    • return a * b + 1
Code
Diff
  • const addArr = (arr) => {
      let sum = arr.reduce((accumulator, currentValue) => accumulator + currentValue, 0);
      return sum || null;
    };
    
    • const addArr = (arr) => {
    • let sum = 0;
    • for (let i = 0; i < arr.length; i++) {
    • sum += arr[i];
    • }
    • let sum = arr.reduce((accumulator, currentValue) => accumulator + currentValue, 0);
    • return sum || null;
    • };